Question bank/JEE Main/Physics

JEE MainPhysicsModerateRigid Body Dynamics

A sphere of mass is given some angular velocity about a
horizontal axis through its centre and gently placed on a plank of mass

The co-efficient of friction between sphere and plank

is[IMAGE]. The plank rests on a smooth horizontal

surface. The initial acceleration of the centre of sphere relative to

the plank will be


Show answer and solution
FBD for sphere & block
a2=frm=μmgma_{2} = \frac{f_{r}}{m} = \frac{\mu mg}{m}
a→1=μgi^{\overrightarrow{a}}_{1} = \mu g\overset{\hat{}}{i}
a→2=−μgi^{\overrightarrow{a}}_{2} = - \mu g\overset{\hat{}}{i}
a→rel=a→1−a→2=2μgi^{\overset{\rightarrow}{a}}_{rel} = {\overset{\rightarrow}{a}}_{1} - {\overset{\rightarrow}{a}}_{2} = 2\mu g\overset{\hat{}}{i}
arel=2μga_{rel} = 2\mu g.

Source: Grass-G / P-10 Physics paper 1 30 October Jee Main.docx

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