Question bank/JEE Main/Physics

The charge appearing on outer surface of external plates when
S_1 and S_2 are open and external plates are uncharged.

A$- \left( \frac{Q}{2} \right)$B$\left( \frac{Q}{2} \right)$CQD- Q

Show answer and solution▾

${\overrightarrow{E}}_{A} = 0$ (Conductor)
-x = x + Q + y - y
2x = - Q
$x = \frac{- Q}{2}$
$- x = \frac{Q}{2}$

Source: Grass-G / P-12 Physics paper 2 Nov.docx