Question bank/JEE Main/Physics

JEE MainPhysicsModerateEM wave

If the magnetic field in a plane electromagnetic wave is given
by

B→=3×10−8sin(1.6×103x+48×1010t)j^ T\overset{\rightarrow}{B} = 3 \times 10^{- 8}sin\left( 1.6 \times 10^{3}x + 48 \times 10^{10}t \right)\overset{\hat{}}{j}\ T,
then what will be expression for electric field?

Show answer and solution
E0B0=C\frac{E_{0}}{B_{0}} = C(speed of light in vacuum)
E0=B0C=3×10−8×3×108E_{0} = B_{0}C = 3 \times 10^{- 8} \times 3 \times 10^{8}
= 9 N/C

So,
E=9sin⁡(1.6×103x+48×1010t)E = 9\sin\left( 1.6 \times 10^{3}x + 48 \times 10^{10}t \right)

Source: Grass-G / P-13 Physics paper 4 Nov.docx

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