JEE MainPhysicsModerateEM wave

In an electromagnetic wave, the electric field oscillates
sinusoidal with amplitude 48 Vm^-1, the RMSvalue of oscillating
magnetic field will be nearly equal to

Show answer and solution

B_{0} = \frac{E_{0}}{c} = \frac{48}{3 \times 10^{8}} = 16 \times 10^{- 8}T

B_{rms} = \frac{B_{0}}{\sqrt{2}} = \frac{16 \times 10^{- 8}}{\sqrt{2}} = 8\sqrt{2} \times 10^{- 8}T

Source: Grass-G / P-13 Physics paper 4 Nov.docx

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