JEE MainPhysicsModerateMagnetic effect of current

Magnitude of Magnetic field at point due to given current
distribution is

Show answer and solution

{\overset{\rightarrow}{B}}_{0} = \frac{\mu_{0}I}{4R}\overset{\hat{}}{j} + \frac{\mu_{0}I}{2\pi R}\overset{\hat{}}{k}

B = \sqrt{\left( \frac{\mu_{0}I}{4R} \right) + \left( \frac{\mu_{0}I}{4\pi R} \right)^{2}}

= \frac{\mu_{0}I}{4\pi R}\sqrt{\pi^{2} + 1}

Source: Grass-G / P-13 Physics paper 4 Nov.docx

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