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JEE MainPhysicsEasyMagnetism

What would be the magnetic moment of given current distribution

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M=I4{π(2R)2−π(R)2}M = \frac{I}{4}\left\{ \pi(2R)^{2} - \pi(R)^{2} \right\} =
3πIR24\frac{3\pi{IR}^{2}}{4}

Source: Grass-G / P-13 Physics paper 4 Nov.docx

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