JEE MainPhysicsModerateMagnetism

The loss of energy in KWH in a specimen of Iron is
$\frac{n}{25}$ . The hysteresis loop of which is equivalent in area equal
to 250 Jm^-3 cycle^-1and frequency 50 min^-1 and specific gravity
of iron is 7.5 and mass of iron is 3.6kg. Find n.

Show answer and solution

Hysteresis loss = 250 cycle
No. of cycle per hour = 50 ×60 = 3000
Hence total loss per hour = 250 × (volume) × (cycles)

= 250 \times \frac{3.6}{7.5 \times 1000} \times 3000

= 360 WH = 0.36 kWH

Source: Grass-G / P-13 Physics paper 4 Nov.docx

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