Question bank/JEE Main/Physics

JEE MainPhysicsToughEMI

A uniform magnetic field B in positive z direction exists in a
circular region of radius R = 5 m. A loop of radius R = 5m lying in x -

y plane encloses the magnetic field at t = 0 and then pulled at uniform. The emf induced (in volts) is the

loop at t = 2 sec is 6V. Then magnitude of 4B is


Show answer and solution
=VB2R2−(vt2)2=VB4R2−V2t2= VB2\sqrt{R^{2} - \left( \frac{vt}{2} \right)^{2}} = VB\sqrt{4R^{2} - V^{2}t^{2}}
6V=4×B4×25−16×46V = 4 \times B\sqrt{4 \times 25 - 16 \times 4}
B=0.25TB = 0.25T

Source: Grass-G / P-13 Physics paper 4 Nov.docx

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