Question bank/JEE Main/Physics

JEE MainPhysicsModerateEM wave

A plane electromagnetic wave of frequency 25 GHz is propagating
in vacuum along the z-direction. At aparticular point in space and time,

the magnetic field is given

by
B→=5×10−8j^T\overset{\rightarrow}{B} = 5 \times 10^{- 8}\overset{\hat{}}{j}T.The
corresponding electric field E is (Speed of light

c = 3 × 10^8ms^-1)

Show answer and solution
EB=c\frac{E}{B} = c
E→\overset{\rightarrow}{E} = B→\overset{\rightarrow}{B} ×
c→\overset{\rightarrow}{c}
=
15i^∨/m15\overset{\hat{}}{i} \vee /m

Source: Grass-G / P-13 Physics paper 4 Nov.docx

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