Question bank/JEE Main/Physics

The distance between two slits in a Young's double slit
experiment is 3 mm. The distance of the screen from the slits is 1 m.
Microwaves of wavelength 1 mm are incident on the plane of the slits
normally. The distance (in cm) of the first maxima on the screen from
the central maxima is $\frac{100}{\sqrt{n}}$. Find n.

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At first maxima [IMAGE]

Source: Grass-G / P-14 Physics paper 7 Nov.docx