Question bank/JEE Main/Physics

If an object is placed at 20 cm in front of a half thin convex
lens of focal length 10 cm as shown in figure then taking object
position as shown the

Ax - coordinate of image is 20 cmBx - coordinate of image is 40 cmCy - coordinate of image is 0.2 cmDy - coordinate of image is 0.4 cm

Show answer and solution▾

$\frac{1}{\text{v}} - \frac{1}{- 20} = \frac{1}{10} \Rightarrow \text{v} = 20$

Source: Grass-G / P-14 Physics paper 7 Nov.docx