Question bank/JEE Main/Physics

JEE MainPhysicsModerateNewton's Laws of Motion

All surfaces are smooth. Find the acceleration (inm/s2m/s^{2}) of
sphere in the given figure.
(g=10m/s2)(g = 10m/s^{2})

Show answer and solution
Suppose of acceleration of wedge a_1, towards right and
acceleration of sphere a_2 downward

[IMAGE]
mg−Ncosθ=ma2mg - Ncos\theta = {ma}_{2}.....(1)
Nsinθ=ma1Nsin\theta = {ma}_{1}.....(2)
[IMAGE] From wedge constraint

a2cosθ=a1sinθa_{2}cos\theta = a_{1}sin\theta
From (i),(ii) & (iii)

a2=gsin⁡2θa_{2} = g\sin^{2}\theta
=5m/s2= 5m/s^{2}

Source: Grass-G / P-16 Physics paper 25 Nov First.docx

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