Question bank/JEE Main/Physics

JEE MainPhysicsEasyCenter of mass

You are shown a photo of a car driven on the inside wall of a
huge vertical cylinder of radius 50 m. The coefficient of static

friction between the car tyres and the cylinder is
μs=0.8\mu_{s} = 0.8. The
minimum speed in (m/s), at which the car can be driven like that is x.

Find x.

Show answer and solution
F. B. D. Of car:-
[IMAGE]
μN=mg\mu N = mg....(1)
N=mv2RN = \frac{mv^{2}}{R}....(2)
From (1) and (2)

V=25m/sV = 25m/s

Source: Grass-G / P-16 Physics paper 25 Nov First.docx

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