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JEE MainPhysicsModerateNewton's Laws of Motion

If acceleration of block B w.r.t. A is 2m/s22m/s^{2}just after the
system is released from rest, then mass(in kg) of block C will be 5m.

Find m. [pulley and string both are massless, take

Show answer and solution
[IMAGE] Given Condition is possible ifaB−aA=2m/s2a_{B} - a_{A} = 2m/s^{2}
And
aA=305=6m/s2⇒aa=8m/s2a_{A} = \frac{30}{5} = 6m/s^{2} \Rightarrow a_{a} = 8m/s^{2}B & C
will move with same acc.
aBa_{B}
⇒mg−50=(m+5)aB\Rightarrow mg - 50 = (m + 5)a_{B}
10m−50=8m+4010m - 50 = 8m + 40
⇒m=45kg\Rightarrow m = 45kg

Source: Grass-G / P-16 Physics paper 25 Nov First.docx

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