JEE MainPhysicsToughProjectile Motion

An elevator of height ascends with constant acceleration
When it crosses a platform bolt drops from the top of the
elevator. If the time for the bolt to hit the floor of the elevator
is $\sqrt{\frac{\lambda h}{g + a}}$ then find $\lambda$ .

Show answer and solution

Choose the floor of the elevator as reference. The observer is
inside the elevator take the downwarddirection as positive.
Acceleration of bolt relative to elevators is

a^{'} = g - ( - a) = g + a

h = \frac{1}{2}a^{'}t^{2} = \frac{1}{2}(g + a)t^{2}

t = \sqrt{\frac{2h}{g + a}}

Source: Grass-G / P-16 Physics paper 25 Nov First.docx

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An elevator of height ascends with constant acceleration When it crosses a platform bolt drops from the top of theelevator. If the time for the bolt to hit the floor of the elevatorisλhg+a\sqrt{\frac{\lambda h}{g + a}}g+aλh​​ then find λ\lambdaλ.

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An elevator of height ascends with constant acceleration
When it crosses a platform bolt drops from the top of the
elevator. If the time for the bolt to hit the floor of the elevator
is $\sqrt{\frac{\lambda h}{g + a}}$ then find $\lambda$ .