Question bank/JEE Main/Physics

The " y ' co-ordinate of the centre of mass of the system of
three rods of length as shown in
figure is: (Assume all rods to be of uniform density)

A$\frac{9a}{8\sqrt{3}}$B$\frac{9a}{16\sqrt{3}}$CzeroD$\frac{8a}{\sqrt{3}}$

Show answer and solution▾

The y-coordinate of centre of mass is
$= \frac{2m(\frac{\sqrt{3}}{2}a) + 2m(0) + 2m(0) + m(\frac{\sqrt{3}}{4}a) + m(\frac{\sqrt{3}}{4}a)}{8m}$
$= \frac{9a}{16\sqrt{3}}$

Source: Grass-G / P-16 Physics paper 25 Nov First.docx