Question bank/JEE Main/Physics

In LC circuit the inductance L= 40 mH and
capacitance$C = 100\mu F$. If a voltage V(t)=10 sin (314 t) is applied
to the circuit, the current in the circuit is given as

A$0.52\ cos314t$B$10\ cos314t$C$5.2\ cos314t$D$0.52\ sin314t$

Show answer and solution▾

$R = 0$
$z = X_{C} - X_{L}$
$= \frac{1}{\omega C} - \omega L$
$= \frac{1}{314 \times 100 \times 10^{- 6}} - 314 \times 40 \times 10^{- 3}$
$= 31.84 - 12.56$
$= 19.28\Omega$
$X_{C} > X_{L}$

Source: Grass-G / P-17 Physics paper 26 Nov Second.docx