Question bank/JEE Main/Physics

JEE MainPhysicsModerateWave Optics

In a single slit diffraction of different light of wavelength
λ\lambda by a slit of with t_1, the size of the central maximum on a
screen at a distance t_2 is

Show answer and solution
t1sinθ=λt_{1}sin\theta = \lambda
θ=λ/t1\theta = \lambda/t_{1}
Width of central Max.
y=2t2θ+t1y = 2t_{2}\theta + t_{1}
y=2t2λt1+t1y = \frac{2t_{2}\lambda}{t_{1}} + t_{1}

Source: Grass-G / P-17 Physics paper 26 Nov Second.docx

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