In the potentiometer circuit shown, AB is a uniform potentiometer wire of length 50 cm, E_1 is 2V accumulator of negligible internal resistance. R_1 and R_2 are and 5 respectively. When K_1 and K_2 are both open, the galvanometer shows no deflection when AJ is 31.25 cm. When K_1 and K_2 both are closed the balance length AJ =5 cm. The emf of cell E_2is ____

JEE MainPhysicsModerateCurrent Electricity

In the potentiometer circuit shown, AB is a $10\Omega$ uniform
potentiometer wire of length 50 cm, E_1 is 2V accumulator of negligible
internal resistance. R_1 and R_2 are $15\Omega$ and 5 $\Omega$
respectively. When K_1 and K_2 are both open, the galvanometer shows
no deflection when AJ is 31.25 cm. When K_1 and K_2 both are closed
the balance length AJ =5 cm. The emf of cell E_2is ____

Show answer and solution

V_{AB} = i10 = \frac{20}{25}

E_{2} = \frac{V_{AB}}{50} \times 31.25

= \frac{20}{25} \times \frac{31.25}{50}

= 0.5V

Source: Grass-G / P-17 Physics paper 26 Nov Second.docx

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