Question bank/JEE Main/Physics

JEE MainPhysicsModerateRay Optics

If an object is placed at 20 cm in front of a half thin convex
lens of focal length 10 cm as shown in figure then taking object
position as shown the.

Show answer and solution
1v+1−20=110⇒v=20\frac{1}{v} + \frac{1}{- 20} = \frac{1}{10} \Rightarrow v = 20
m=−1m = - 1

Source: Grass-G / P-17 Physics paper 26 Nov Second.docx

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