Question bank/JEE Main/Physics

JEE MainPhysicsToughNewton's Laws of Motion

A plank having mass M is placed on smooth horizontal surface.
Block of mass m is placed on it coefficient of friction between block

and plank is
μ0+kx\mu_{0} + kx,where k is constant and x is relative
displacement of block w.r.t. plank. A force F is applied on block where

F=at, where a=10; t is in second. Find
t0t_{0} to when relative motion
will occur between block and plank (use
g=10m/s2g = 10m/s^{2}).

Show answer and solution
Let at time t_o relative motion will occur.
[IMAGE]
μ0mg=Ma\mu_{0}mg = Ma..... (1)
[IMAGE]
10t0−μ0mg=ma10t_{0} - \mu_{0}mg = ma..... (2)
From (1) and (2);

t0=μ0m+μ0m2Mt_{0} = \mu_{0}m + \frac{\mu_{0}m^{2}}{M}

Source: Grass-G / P-18 Physics paper 27 Nov Third.docx

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