Question bank/JEE Main/Physics

JEE MainPhysicsModerateNewton's Laws of Motion

In the arrangement shown in the figure there is friction only
between the light string and the sharp spike at the point P. When the

blocks are in motion, the tensions in the vertical and horizontal

sections of the string are 4 N & 3 N respectively. The co-efficient of

friction between the string and the spike is equal to

Show answer and solution
[IMAGE] N = 5
on string

4−3−μN=04 - 3 - \mu N = 0
μN=1\mu N = 1
μ=0.2\mu = 0.2

Source: Grass-G / P-18 Physics paper 27 Nov Third.docx

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