Question bank/JEE Main/Physics

JEE MainPhysicsModerateElectromagnetic induction

In a fluorescent lamp choke (a small transformer) 100 V of
reverse voltage is produced when the choke current changes uniformly
from 0.25 A to 0 in a duration of 0.025 ms. The self-inductance of the
choke(in mH) is estimated to be 2.5n. Find n.

Show answer and solution
100=L(0.25)0.025×103100 = \frac{L(0.25)}{0.025} \times 10^{3}
∴L=100×10−4H\therefore L = 100 \times 10^{- 4}H
=10mH= 10mH

Source: Grass-G / P-19 Physics paper 28 Nov Fourth.docx

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