Question bank/JEE Main/Physics

A vessel of depth 2h is half filled with a liquid of refractive
index[IMAGE] and the upper half with another liquid of
refractive index[IMAGE]. The liquids are immiscible. The
apparent depth of the inner surface of thebottom of vessel will be

A$\frac{h}{3\sqrt{2}}$B$\frac{3}{4}h\sqrt{2}$C$\frac{h}{\sqrt{2}}$D$\frac{h}{2(\sqrt{2} + 1)}$

Show answer and solution▾

$d = \frac{h}{\sqrt{2}} + \frac{h}{2\sqrt{2}}$

Source: Grass-G / P-20 Physcis Paper 12 Dec.docx