Question bank/JEE Main/Physics

JEE MainPhysicsModerateMagnetism

A long, straight wire of radius a carries a current distributed
uniformly over its cross-section. The ratioof the magnetic fields due

to the wire at distance[IMAGE] and 2a, respectively from

the axis of the wire is n/3. Find n.

Show answer and solution
Using Ampere's circuital law:
BB=μ0i2π(2a)B_{B} = \frac{\mu_{0}i}{2\pi(2a)}
BABB=46=23\frac{B_{A}}{B_{B}} = \frac{4}{6} = \frac{2}{3}

Source: Grass-G / P-20 Physcis Paper 12 Dec.docx

Need a video for this idea?

Scan any doubt from your notes and get a whiteboard explanation.