Question bank/JEE Main/Physics

Take two infinite planes with same surface charge density. Place
them as shown it the figure. The electric field in the region between
them is given by

A$\frac{\sigma}{2\epsilon_{0}}\lbrack(1 + \sqrt{3})\overset{\hat{}}{y} - \frac{\overset{\hat{}}{x}}{2}\rbrack$B$\frac{\sigma}{2\epsilon_{0}}\lbrack(1 - \frac{\sqrt{3}}{2})\overset{\hat{}}{y} - \frac{\overset{\hat{}}{x}}{2}\rbrack$C$\frac{\sigma}{2\epsilon_{0}}\lbrack(1 + \sqrt{3})\overset{\hat{}}{y} + \frac{\overset{\hat{}}{x}}{2}\rbrack$D$\frac{\sigma}{\epsilon_{0}}\lbrack(1 + \frac{\sqrt{3}}{2})\overset{\hat{}}{y} + \frac{\overset{\hat{}}{x}}{2}\rbrack$

Show answer and solution▾

$\overset{\rightarrow}{E} = \frac{\sigma}{2\varepsilon_{0}}\lbrack(1 - \frac{\sqrt{3}}{2})\overset{\hat{}}{y} - \frac{1}{2}\overset{\hat{}}{x}\rbrack$

Source: Grass-G / P-20 Physcis Paper 12 Dec.docx