Question bank/JEE Main/Physics

The maximum peak to peak voltage of an AM wave is 24 mV and the
minimum peak to peak voltage is8 mV. The modulation factor is.

A10B20C25D50

Show answer and solution▾

Here ¼;gk¡½, $V_{\max} = \frac{24}{2}$=12mV and¼rFkk½
$V_{\min} = \frac{8}{2} = 4mV$

Source: Grass-G / P-21 Physcis Paper 19 Dec Hindi Eng..docx