Question bank/JEE Main/Physics

JEE MainPhysicsModerateElectrostatics

A 1 µF1\ µF capacitor is connected in the circuit shown below. The
e.m.f. of the cell is 3 volts and internalresistance is 0.5 ohms. The

resistors R_1and R_2have values 4 ohms and 1 ohm respectively.

Thecharge (in
µC)µC) on the capacitor in steady state must be

Show answer and solution
In steady state no current flows through capacitor. The
potential difference across capacitor andresistor of resistance R_2is

same.

∴\mathbf{\therefore} charge on capacitor
=CV=C×3=1μF×3=3μC= CV = C \times 3 = 1\mu F \times 3 = 3\mu C.
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Source: Grass-G / P-21 Physcis Paper 19 Dec Hindi Eng..docx

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