JEE MainPhysicsModerateCommunication system

For an amplitude modulated wave maximum and minimum amplitude
are 10 V and 2 V respectively.Modulation index is n/3. Find n:
10 V rFkk 2 V

Show answer and solution

A_max = A_m + A_c = 10
A_min = A_c - A_m = 2
A_c = 6 V
A_m = 4 V

m = \frac{A_{m}}{A_{c}} = \frac{4}{6} = \frac{2}{3}

Source: Grass-G / P-21 Physcis Paper 19 Dec Hindi Eng..docx

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