Question bank/JEE Main/Physics

JEE MainPhysicsModerateNuclear Physics

The activity of a radioactive sample falls from
[IMAGE] in 30 minutes. Its half life is close to


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[IMAGE] (i) (ii)
⇒ln2ln(7/5)=t12(30min⁡)⇒(2.06004)30=t12=61.8min\Rightarrow \text{\quad}\frac{ln2}{ln(7/5)} = \frac{t_{\frac{1}{2}}}{(30\min)} \Rightarrow \text{\quad}(2.06004)30 = t_{\frac{1}{2}} = 61.8\text{min}


Source: Grass-G / P-23 Physcis Paper 31 Dec FST.docx

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