JEE MainPhysicsModerateMechanical properties of liquid

The pressure gauge reading in meter of water column shown in the
given figure will be

Show answer and solution

P_{0} + \rho_{w}g1 + \rho_{wg}0.2 - \rho_{Hg}g0.2 = P_{0}

P - P_{0} = \rho_{Hg}g0.2 - \rho_{w}g(1.2) = 14896

14896 = \rho_{wgh}

h = 1.52

Source: Grass-G / P-24 Physcis Paper 31 Dec.docx

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