Question bank/JEE Main/Physics

JEE MainPhysicsModerateMechanical Properties of Fluids

The densities of wood and benzene at 0°C
are
 880kgm−3\ 880{kgm}^{- 3}and  900 kgm−3\ 900\ {kgm}^{- 3}, respectively. The
coefficients of volume expansion of wood is

1.2×10−3∘C−11.2 \times 10^{- 3^{{^\circ}}}C^{- 1} and that of benzene is
1.5×10−3∘C−11.5 \times 10^{- 3^{{^\circ}}}C^{- 1}. Value of temperature (in °C) at
which a piece of this wood would just sink in benzene at the same

temperature is T. Then find value of [IMAGE] (where T is

temperature in °C).

Show answer and solution
For just sink condition
ρow (1−γw ΔT)=ρob (1−γbΔT)\rho_{ow\ }\left( 1 - \gamma_{w\ }\Delta T \right) = \rho_{ob\ }\left( 1 - \gamma_{b}\Delta T \right)
880(1−1.2×103(T−0))=900(1−1.5×10−3(T−0))880\left( 1 - 1.2 \times 10^{3}(T - 0) \right) = 900\left( 1 - 1.5 \times 10^{- 3}(T - 0) \right)
T10−3(1.5−1.2)=900−880T10^{- 3}(1.5 - 1.2) = 900 - 880
T×10−3×0.3=20T \times 10^{- 3} \times 0.3 = 20
T=20×1043∘CT = \frac{20 \times 10^{4}}{3}{^\circ}C

Source: Grass-G / P-24 Physcis Paper 31 Dec.docx

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