JEE MainPhysicsModerateKinetic Theory of Gases

The ratio of r.m.s. speed to the r.ms. angular speed of a
diatomic gas at certain temperature is:(assume m= mass of one molecule
mass I = moment of inertia of the molecules)
ewy ekfu, m =,d v.kq
vk.kfod nzO;eku I = v.kqvksa

Show answer and solution

\frac{1}{2}{mV}^{2} = \frac{3}{2}kT

\frac{1}{2}I\omega^{2} = \frac{2}{2}kT

\frac{V}{\omega} = \sqrt{\frac{3I}{2m}}

Source: Grass-G / Ph-25 Physics paper 7 Jan.docx

Need a video for this idea?

Scan any doubt from your notes and get a whiteboard explanation.