Question bank/JEE Main/Physics

JEE MainPhysicsModerateKinetic Theory of Gases

Pressure versus temperature graph of the ideal gas at constant
volume V of an ideal gas is shown by a straight line A. Now, pressure P

of the gas is doubled and the volume is halved: then the corresponding

pressure versus temperature graph will be shown by the line:-,d vkn"kZ xSLk ds fLFkj xSl dk ncko cuke rkieku xzkQ

rkieku xzkQ ykbu tk,xkA

Show answer and solution
P=nRTV=mRTMVP = \frac{nRT}{V} = \frac{mRT}{MV}
(Where[IMAGE] number of moles)

So, at constant volume pressure versus temperature graph is a straight

line passing through origin with slope mR/MV. As volume is halved,

slope becomes two times. Therefore, pressure versus temperature graph

will be shown by the line B.

eku ds fo:) fLFkj <ky lkFk mRifÙk

<yku nks xquk gks A ncko

cuke rkieku xzkQ tk,xkA

Source: Grass-G / Ph-25 Physics paper 7 Jan.docx

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