Question bank/JEE Main/Physics

JEE MainPhysicsModerateThermodynamics

Figure below shows two paths that may be taken by a gas to go
from a state A to a state C.

[IMAGE] In process AB, 400J of heat is added to the system and in process BC,

100 J of heat is added to the system. The heat absorbed by the system

in the process AC will be:;gk¡ nks iFk ftu

A ls voLFkk B rd ys tk;k tk ldrk gSA

s AB] çØe esa 400 J rFkk çØe BC


Show answer and solution
For a complete cycle
iw.kZ pfØ; çØe ds fy,

Q_cycle = W_cycle

+400+100+QC→A=12(2×10−3)(4×104)+ 400 + 100 + Q_{C \rightarrow A} = \frac{1}{2}\left( 2 \times 10^{- 3} \right)\left( 4 \times 10^{4} \right)
⇒ Q~C→ A~ = - 460 J

⇒ Q_A→C = + 460 J

Source: Grass-G / Ph-25 Physics paper 7 Jan.docx

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