Question bank/JEE Main/Physics

JEE MainPhysicsModerateMechanical properties of liquid

If two soap bubbles of different radii are connected by a tube:;fn fofHkUu f= nks lkcqu ds cqycqyksa

Show answer and solution
The excess pressure inside the soap bubble in inversely
proportional to radius of soap bubble i.e.
P∝1/rP \propto 1/r, r being the
radius of bubble. It follows that pressure inside a smaller bubble is

greater than that inside a bigger bubble. Thus, if these two bubbles are

connected by a tube, air will flow from smaller bubble to bigger bubble

and the bigger bubble grows at the expense of the smaller one.

cqycqys cqycqys dh f= Øekuqikrh gksrk gSA

P∝1/rP \propto 1/r] tgk¡ rcqycqys dh f= SA vr NksVs cqycqys esa cM+s
cqycqys dh rqyuk gskxk;fn nksuksa cqycqyksa dks

ufy tksM+k rks gok NksVs cqycqys

Source: Grass-G / Ph-26 Physics paper 1 15 Jan.docx

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