Question bank/JEE Main/Physics

A non-viscous fluid of density [IMAGE] is
flowing in a tube as shown in figure. Area of section

Ais double
that of sectionB. Centre of mass of sectionCWork done by gravitational force per unit volume from
sectionDWork done by elastic forces (pressure) per unit volume from
section

Show answer and solution▾

Applying Bernoulli is equation from section-(1) and (2)
[IMAGE] and $P_{1} - P_{2} = \rho g(2h)$
Solving we get, [IMAGE] (3) Work done by gravitation force per unit volume = negative of the
increase in gravitational potential energy per unit volume =
$- (\rho gh)$
(4) Work done by elastic force per unit volume = decrease in
pressure = [IMAGE] = $2\rho gh$
TOPIC: Fluid dynamics
SUB TOPIC: Bernoulli's theorem

Source: Grass-G / Ph-28 Physics paper FST 16 Jan.docx