Question bank/NEET UG/Physics

NEET UGPhysicsModerateNEET 2025

A ball of mass 0.5 kg is dropped from a height of 40 m. The ball hits the ground and rises to a height of 10 m. The impulse imparted to the ball during its collision with the ground is (Take g=9.8g = 9.8 m/s²)

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v1=2gh1v_1 = \sqrt{2gh_1}

=2×9.8×40= \sqrt{2 \times 9.8 \times 40}

v1=784=28v_1 = \sqrt{784} = 28 m s⁻¹

and v2=2gh2=2×9.8×10v_2 = \sqrt{2gh_2} = \sqrt{2 \times 9.8 \times 10}

=196=14= \sqrt{196} = 14 m s⁻¹

Impulse =Δp⃗=m(v⃗f−v⃗i)=m(v⃗2−v⃗1)= \Delta \vec{p} = m(\vec{v}_f - \vec{v}_i) = m(\vec{v}_2 - \vec{v}_1)

=12(14−(−28))= \frac{1}{2}(14 - (-28))

=21= 21 NS

Source: geekyrakshit/indian-exam-questions / neet2025-code45

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