Question bank/NEET UG/Physics

NEET UGPhysicsModerateNEET 2025

AB is a part of an electrical circuit (see figure). The potential difference "VA−VBV_A - V_B", at the instant when current i=2i = 2 A and is increasing at a rate of 1 amp/second is:

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Sol.
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Given, I=2AI = 2A and didt=+1A/s\frac{di}{dt} = +1A/s
VA−Ldidt−5−i×2=VBV_A - L\frac{di}{dt} - 5 - i \times 2 = V_B
⇒VA−1×1−5−2×2=VB\Rightarrow V_A - 1 \times 1 - 5 - 2 \times 2 = V_B
⇒VA−VB=10\Rightarrow V_A - V_B = 10 volt

Source: geekyrakshit/indian-exam-questions / neet2025-code45

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