Question bank/NEET UG/Physics

NEET UGPhysicsModerateNEET 2025

To an ac power supply of 220 V at 50 Hz, a resistor of 20 Ω, a capacitor of reactance 25 Ω and an inductor of reactance 45 Ω are connected in series. The corresponding current in the circuit and the phase angle between the current and the voltage is, respectively

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Sol. XL=45 WX_L = 45\text{ W}, XC=25 WX_C = 25\text{ W}, R=20 WR = 20\text{ W}

I=220(XL−XC)2+R2=220(45−25)2+202I = \frac{220}{\sqrt{(X_L-X_C)^2+R^2}} = \frac{220}{\sqrt{(45-25)^2+20^2}}

=22022=112=7.779 A= \frac{220}{2\sqrt{2}} = \frac{11}{\sqrt{2}} = 7.779\text{ A}

tan⁡ϕ=XL−XCR=45−2520=1\tan\phi = \frac{X_L-X_C}{R} = \frac{45-25}{20} = 1

ϕ=45°\phi = 45°

Source: geekyrakshit/indian-exam-questions / neet2025-code45

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