Question bank/NEET UG/Physics

NEET UGPhysicsModerateNEET 2025

Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.). The least division in the M.S. is 0.1 cm and the zero of V.S. is at x = 0.1 cm when the jaws of Vernier callipers are closed.
If the main scale reading for the diameter is M = 5 cm and the number of coinciding vernier division is 8, the measured diameter after zero error correction, is

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Sol. Least count = 1MSD – 1VSD

= 1 MSD−910MSD1\,\text{MSD} - \frac{9}{10}\text{MSD}

= 110MSD\frac{1}{10}\text{MSD}

= 110×0.1 cm=0.01 cm\frac{1}{10} \times 0.1\,\text{cm} = 0.01\,\text{cm}

Zero error = +0.1 cm

Source: geekyrakshit/indian-exam-questions / neet2025-code45

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