De-Broglie wavelength of an electron orbiting in the state of hydrogen atom is close to (Given Bohr radius = 0.052 nm)

NEET UGPhysicsModerateNEET 2025

De-Broglie wavelength of an electron orbiting in the $n=2$ state of hydrogen atom is close to
(Given Bohr radius = 0.052 nm)

Show answer and solution

Sol.

r = 0.052 n^2

For

n=2

r = 0.052 \times 4

= 0.208

Mvr = \frac{nh}{2\pi}

\lambda = \frac{h}{Mv} = \pi r

= 3.14 \times 0.208

= 0.65317

\approx 0.67

Source: geekyrakshit/indian-exam-questions / neet2025-code45

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