Question bank/NEET UG/Physics

NEET UGPhysicsModerateNEET 2025

A physical quantity PP is related to four observations aa, bb, cc and dd as follows:
P=a3b2/cdP = a^3b^2 / c\sqrt{d}

The percentage errors of measurement in
aa, bb, cc and dd are 1%, 3%, 2%, and 4% respectively. The percentage error in the quantity PP is

Show answer and solution
Sol. Maximum % error in P=ΔPP×100=3(Δaa×100)+2(Δbb×100)+(Δcc×100)+12(Δdd×100)P = \frac{\Delta P}{P} \times 100 = 3\left(\frac{\Delta a}{a} \times 100\right) + 2\left(\frac{\Delta b}{b} \times 100\right) + \left(\frac{\Delta c}{c} \times 100\right) + \frac{1}{2}\left(\frac{\Delta d}{d} \times 100\right)
=3×(1)+2×(3)+(2)+12(4)= 3 \times (1) + 2 \times (3) + (2) + \frac{1}{2}(4)
=13%= 13\%

Source: geekyrakshit/indian-exam-questions / neet2025-code45

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