Question bank/NEET UG/Chemistry
NEET UGChemistryModerateNEET 2025
Consider the following compounds :
KO, HO and HSO
The oxidation state of the underlined elements (K in KO, O in HO and S in HSO) in them are, respectively,


Show answer and solution
KO → Alkali metal always shows +1 oxidation state. Therefore oxidation state of K is +1.
HO → <image_1> Oxidation state of oxygen in HO is −1.
HSO → <image_2> Oxidation state of sulphur in HSO is +6.
HO → <image_1> Oxidation state of oxygen in HO is −1.
HSO → <image_2> Oxidation state of sulphur in HSO is +6.
Source: geekyrakshit/indian-exam-questions / neet2025-code45
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