Question bank/NEET UG/Chemistry

NEET UGChemistryModerateNEET 2025

Consider the following compounds :
KO
2_{2}, H2_{2}O2_{2} and H2_{2}SO4_{4}

The oxidation state of the underlined elements (K in KO
2_{2}, O in H2_{2}O2_{2} and S in H2_{2}SO4_{4}) in them are, respectively,

Show answer and solution
KO2_{2} → Alkali metal always shows +1 oxidation state. Therefore oxidation state of K is +1.
H
2_{2}O2_{2} → <image_1> Oxidation state of oxygen in H2_{2}O2_{2} is −1.
H
2_{2}SO4_{4} → <image_2> Oxidation state of sulphur in H2_{2}SO4_{4} is +6.

Source: geekyrakshit/indian-exam-questions / neet2025-code45

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