Question bank/NEET UG/Chemistry
NEET UGChemistryModerateNEET 2025
Given below are two statements :
Statement-I : Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273 - 278 K. It decomposes easily in the dry state.
Statement-II : Insertion of iodine into the benzene ring is difficult and hence iodobenzene is prepared through the reaction of benzenediazonium salt with KI.
In the light of the above statements, choose the most appropriate answer from the options given below :
Show answer and solution
Sol. Benzene diazonium chloride is prepared by the reaction of aniline with nitrous acid at 273-278 K.
Nitrous acid is produced in the reaction mixture by reaction of NaNO₂ with HCl.
Benzene diazonium chloride decomposes easily in the dry state
Iodobenzene is prepared by shaking benzene diazonium salt with KI because direct insertion of iodine into benzene ring is difficult
<image_1>
Nitrous acid is produced in the reaction mixture by reaction of NaNO₂ with HCl.
Benzene diazonium chloride decomposes easily in the dry state
Iodobenzene is prepared by shaking benzene diazonium salt with KI because direct insertion of iodine into benzene ring is difficult
<image_1>
Source: geekyrakshit/indian-exam-questions / neet2025-code45
Need a video for this idea?
Scan any doubt from your notes and get a whiteboard explanation.