Question bank/NEET UG/Physics

NEET UGPhysicsModerateRe-NEET 2026

Three identical capacitors, *P*, *Q* and *S*, each of the capacitance *C*, are connected to a battery of voltage *V*, as shown in the figure. If the energy stored in the capacitor *P* and total energy stored in the system are UPU_P and UTU_T, respectively, then the ratio UPUT\frac{U_P}{U_T} is:
[IMAGE]

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Sol. CP=CQ=CS=CC_P = C_Q = C_S = C
<image_2>
UP=12C(V2)2=12CV24=CV28U_P = \frac{1}{2}C{\left(\frac{V}{2}\right)}^2 = \frac{1}{2}\frac{CV^2}{4} = \frac{CV^2}{8}
UT=UP+UQ+US=12C(V2)2+12C(V2)2+12CV2U_T = U_P + U_Q + U_S = \frac{1}{2}C{\left(\frac{V}{2}\right)}^2 + \frac{1}{2}C{\left(\frac{V}{2}\right)}^2 + \frac{1}{2}CV^2
=CV28+CV28+12CV2=6CV28=34CV2= \frac{CV^2}{8} + \frac{CV^2}{8} + \frac{1}{2}CV^2 = \frac{6CV^2}{8} = \frac{3}{4}CV^2
UPUT=CV28×3CV24=16\frac{U_P}{U_T} = \frac{CV^2}{8 \times \frac{3CV^2}{4}} = \frac{1}{6}

Source: geekyrakshit/indian-exam-questions / reneet2026-code50

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