Question bank/NEET UG/Physics

NEET UGPhysicsModerateRe-NEET 2026

Two planets P1P_1 and P2P_2 with equal mass have radii R1R_1 and R2R_2, respectively, where R2=R12R_2 = \frac{R_1}{2}. The escape speeds of P1P_1 and P2P_2 are v1v_1 and v2v_2, respectively. Then v2v1\frac{v_2}{v_1} is:

Show answer and solution
Sol. Ve=2gR=2GMRV_e = \sqrt{2gR} = \sqrt{\frac{2GM}{R}}
Ve∝1RV_e \propto \frac{1}{\sqrt{R}} [∵M\because M = constant]
Ve2Ve1=R1R2=2\frac{V_{e2}}{V_{e1}} = \sqrt{\frac{R_1}{R_2}} = \sqrt{2}

Source: geekyrakshit/indian-exam-questions / reneet2026-code50

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