Question bank/NEET UG/Physics

NEET UGPhysicsModerateRe-NEET 2026

The temperature of a metallic sphere of radius RR is increased by a small amount ΔT\Delta T. If the linear coefficient of thermal expansion of the metal is α\alpha, the approximate increase in the volume of the sphere is:

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For the metallic sphere, ΔRR=αΔT\frac{\Delta R}{R} = \alpha\Delta T
Volume of the sphere, V=43πR3V = \frac{4}{3}\pi R^3
∴ΔVV=3ΔRR\therefore \frac{\Delta V}{V} = 3 \frac{\Delta R}{R}
Increase in volume = ΔV=3(ΔRR)(43πR3)=4πR3αΔT\Delta V = 3\left(\frac{\Delta R}{R}\right) \left(\frac{4}{3}\pi R^3\right) = 4\pi R^3 \alpha \Delta T

Source: geekyrakshit/indian-exam-questions / reneet2026-code50

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