Question bank/NEET UG/Chemistry

NEET UGChemistryModerateRe-NEET 2026

The correct order of solubility of the given salts in water at 298 K is

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Sol. AgBr(s)⇌Ag+(aq.)+Br−(aq.)AgBr(s) \rightleftharpoons Ag^+(aq.) + Br^-(aq.)
Ksp=5×10−13=S2K_{sp} = 5 \times 10^{-13} = S^2
S=5×10−13S = \sqrt{5 \times 10^{-13}}, S=7.07×10−7S = 7.07 \times 10^{-7} mol/l
Zn(OH)2(s)⇌Zn2+(aq.)+2OH−(aq.)Zn(OH)_2(s) \rightleftharpoons Zn^{2+}(aq.) + 2OH^-(aq.)
Ksp=10−15=(S)(2S)2K_{sp} = 10^{-15} = (S)(2S)^2
4S3=10−154S^3 = 10^{-15} , S=0.63×10−5=6.3×10−6S = 0.63 \times 10^{-5} = 6.3 \times 10^{-6} mol/l
Hg2Cl2(s)⇌Hg22+(aq.)+2Cl−(aq.)Hg_2Cl_2(s) \rightleftharpoons Hg_2^{2+}(aq.) + 2Cl^-(aq.)
Ksp=1.3×10−18=4S3K_{sp} = 1.3 \times 10^{-18} = 4S^3, S=0.69×10−6=6.9×10−7S = 0.69 \times 10^{-6} = 6.9 \times 10^{-7} mol/l
The correct order of solubility is:

Zn(OH)2>AgBr>Hg2Cl2Zn(OH)_2 > AgBr > Hg_2Cl_2

Source: geekyrakshit/indian-exam-questions / reneet2026-code50

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