Question bank/NEET UG/Chemistry

NEET UGChemistryModerateRe-NEET 2026

For a salt XY, which is a strong electrolyte, the plot of Λm\Lambda_m versus c\sqrt{c} has a slope of –90.0 S cm² mol⁻³/² L¹/² at 298 K. At 0.01 M concentration of XY, the value of Λm\Lambda_m is 145.0 S cm² mol⁻¹. The limiting molar conductivity of Y⁻ ion (λY−°\lambda_{Y⁻}^°, in S cm² mol⁻¹) at 298 K will be

(Given :
λX+°\lambda_{X^+}^° = 74.0 S cm² mol⁻¹)

Show answer and solution
Sol. y = mx + c

slope = –90


According to
λm=λmo−Ac\lambda_m = \lambda_m^o - A\sqrt{c}

145=λmo−90×0.1145 = \lambda_m^o - 90 \times 0.1

λmo=154\lambda_m^o = 154 S cm² mol⁻¹

λm(XY)o=λX+o+λY−o\lambda_{m(XY)}^o = \lambda_{X^+}^o + \lambda_{Y⁻}^o

154=74+λY−o154 = 74 + \lambda_{Y⁻}^o

λY−o=80\lambda_{Y⁻}^o = 80 S cm² mol⁻¹

Source: geekyrakshit/indian-exam-questions / reneet2026-code50

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